The Chemical Bond
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Extra exercise 2: The momentum representation

When one writes a wavefunction with coordinates as arguments, one works in the coordinate representation. It is also possible to work in the momentum representation: the momenta are then the arguments. If y(x) is a wavefunction in the coordinate representation and j(p) the same wavefunction in momentum representation then

j(p)
= 1

Ö

2p
ó
õ
infinity

-infinity 
dx ei2ppx/hy(x),
and
y(x)
= 1

Ö

2p
ó
õ
infinity

-infinity 
dp e-i2ppx/hj(p).

a) Write the following wavefunctions in momentum representation.

yn(x) = ì
ï
í
ï
î

Ö
 

2/p
 
sin(nx),
if 0 £ x £ p,
0,
otherwise
with n = 1,2,3,.... These are solutions of the Schrödinger equation for a particle in a box with walls at x = 0 and x = a

b) Calculate
ó
õ
infinity

-infinity 
dp pm|j1(p)|2

ó
õ
infinity

-infinity 
dp pm|j1(p)|2
for m = 1 and m = 2. Compare the results with the expectation values for p and p2.

Last updated: Wednesday, April 10, 2002
© Dr. A.P.J. Jansen