The Chemical Bond
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Fine: Chapter 5, Problem 33

Problem   On page 218: Write down the electronic configuration for each of the following:

  1. A ground-state arsenic atom (Z = 33)
  2. A ground-state titanium atom (Z = 22)
  3. A ground-state iodine atom (Z = 53)
Subject   Electron Configuration, Fine: pages 197-207.

Solution   We could actually just look at table 5.7 on page 205, look up Z and write down what we find, as the three atoms are in their ground state. Doing this gives us:

  1. The arsenic atom has a ground-state [Ar]4s23d104p3 configuration. To be complete, we should also specify that [Ar] = [Ne]3s23p6 = [He]2s22p6   3s23p6 = 1s2   2s22p6   3s23p6. Then, the arsenic atom, As has the electronic configuration: 1s2   2s22p6   3s23p6   4s23d104p3.
  2. The titanium atom has a ground-state [Ar]4s23d2 configuration. To be complete, we should also specify that [Ar] = 1s2   2s22p6   3s23p6 to arrive at the configuration: 1s2   2s22p6   3s23p6   4s23d2.
  3. The iodine atom has ground-state configuration [Kr]5s24d105p5. With [Kr] = [Ar]4s23d104p6 = 1s2   2s22p6   3s23p6   4s23d104p6, we eventually arrive at the electronic configuration: 1s2   2s22p6   3s23p6   4s23d104p6   5s24d105p5.

Last updated: Wednesday, April 03, 2002
© Dr. A.P.J. Jansen