|
|||||||||||||||||||||
MO diagrams of interacting orbitals |
|||||||||||||||||||||
|
The following MO diagram shows how the orbitals of O2 are formed from those of the oxygen atoms. |
|||||||||||||||||||||
![]() |
|||||||||||||||||||||
| On the left and on the right are the orbitals of the oxygen atoms with their occupation. In the center are the orbitals of the O2
molecule. The dashed lines connecting the orbitals in the center to
those on the left and right indicate which atomic orbitals of oxygen
form the molecular orbitals of O2. So s3 is formed from
(i.e., is a linear combination of) the 2s orbitals. This is a bonding
orbital. The s4* orbital is the antibonding orbital that the 2s form (see "Qualitative MO theory'').
The p1 and the p2* levels are the bonding and antibonding levels, respectively, formed from the 2p orbitals that are perpendicular to the molecular axis. The two 2p orbitals lying along the molecular axis form s5 and s6*. Strictly speaking these 2p orbitals also contribute to s3 and s4*, and the 2s orbitals contribute to s5 and s6*. These contributions are relatively small, however, and are therefore not shown. Such MO diagrams as the one above can be drawn for many other molecules as well. They can be obtained from quantum chemical calculations, or from applying the rules of qualitative MO theory. Their main purpose is to show why a molecule is formed by showing which electrons get a lower energy when the molecule is formed. For O2 we see that the electrons in s5 have a lower energy than two electrons in 2p orbitals of oxygen atoms. The two electrons in p2* have a higher energy, but this is more than compensated by four electrons in p1. The occupation of the orbitals tells us the bond order of a bond, and what type of bond it is. For O2 we have a bond order of two (i.e., a double bond), and there is a s and a p bond. Each pair of electrons in a bonding orbital increases the bond order by one. Each pair of electrons in an antibonding orbital decreases the bond order by one. The bonding s3 an the antibonding s4* lead to no net bonding, but, because s6* is vacant, s5 is a s bond. There are two more electrons in the p bonding then in the antibonding orbitals, so we have one p bond as well. |
|||||||||||||||||||||
|
|
|||||||||||||||||||||
|
|||||||||||||||||||||
|
Last updated:
© Dr. A.P.J. Jansen |
|||||||||||||||||||||